# QA – Placement Quizzes | Probability | Question 15

A box contains 5 green, 4 yellow and 3 white balls. Three balls are drawn at random. What is the probability that they are not of the same color?**(A)** 3/44

**(B)** 3/55

**(C)** 52/55

**(D)** 41/44

**Answer:** **(D)****Explanation:** Let S be the event of drawing 3 balls out of 12. Then,

n(S) = ^{12}C_{3} = 220.

Let E be the event of drawing 3 balls of the same colour. Then,

n(E) = ^{5}C_{3} + ^{4}C_{3} + ^{3}C_{3} = 10 + 4 + 1 = 15. And,

P(E) = n(E)/n(S) = 15/220 = 3/44.

Therefore, required probability = 1 – 3/44 = 41/44.

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